如何显式实现两个接口的成员(C# 编程指南)
显式接口实现还允许程序员实现具有相同成员名称的两个接口,并为每个接口成员各提供一个单独的实现。 本示例同时以公制单位和英制单位显示框的尺寸。 Box 类实现 IEnglishDimensions 和 IMetricDimensions 两个接口,它们表示不同的度量系统。 两个接口有相同的成员名称 Length 和 Width。
示例
// Declare the English units interface:
interface IEnglishDimensions
{
float Length();
float Width();
}
// Declare the metric units interface:
interface IMetricDimensions
{
float Length();
float Width();
}
// Declare the Box class that implements the two interfaces:
// IEnglishDimensions and IMetricDimensions:
class Box : IEnglishDimensions, IMetricDimensions
{
float lengthInches;
float widthInches;
public Box(float lengthInches, float widthInches)
{
this.lengthInches = lengthInches;
this.widthInches = widthInches;
}
// Explicitly implement the members of IEnglishDimensions:
float IEnglishDimensions.Length() => lengthInches;
float IEnglishDimensions.Width() => widthInches;
// Explicitly implement the members of IMetricDimensions:
float IMetricDimensions.Length() => lengthInches * 2.54f;
float IMetricDimensions.Width() => widthInches * 2.54f;
static void Main()
{
// Declare a class instance box1:
Box box1 = new Box(30.0f, 20.0f);
// Declare an instance of the English units interface:
IEnglishDimensions eDimensions = box1;
// Declare an instance of the metric units interface:
IMetricDimensions mDimensions = box1;
// Print dimensions in English units:
System.Console.WriteLine("Length(in): {0}", eDimensions.Length());
System.Console.WriteLine("Width (in): {0}", eDimensions.Width());
// Print dimensions in metric units:
System.Console.WriteLine("Length(cm): {0}", mDimensions.Length());
System.Console.WriteLine("Width (cm): {0}", mDimensions.Width());
}
}
/* Output:
Length(in): 30
Width (in): 20
Length(cm): 76.2
Width (cm): 50.8
*/
可靠编程
如果希望默认度量采用英制单位,请正常实现 Length 和 Width 方法,并从 IMetricDimensions 接口显式实现 Length 和 Width 方法:
// Normal implementation:
public float Length() => lengthInches;
public float Width() => widthInches;
// Explicit implementation:
float IMetricDimensions.Length() => lengthInches * 2.54f;
float IMetricDimensions.Width() => widthInches * 2.54f;
这种情况下,可以从类实例访问英制单位,从接口实例访问公制单位:
public static void Test()
{
Box box1 = new Box(30.0f, 20.0f);
IMetricDimensions mDimensions = box1;
System.Console.WriteLine("Length(in): {0}", box1.Length());
System.Console.WriteLine("Width (in): {0}", box1.Width());
System.Console.WriteLine("Length(cm): {0}", mDimensions.Length());
System.Console.WriteLine("Width (cm): {0}", mDimensions.Width());
}